Write a program to find length and sum of digits in a number.

Lets first figure out the logic of getting digits of a number, once we get the digit we can count them and also find addition.

suppose we have a digit= 543374. lets figure out it as;

Step 1:

reminder = 543374%10 = 4

digit =543374/10 =54337     (1 digit)

Step 2:

reminder = 54337%10 = 7

digit = 54337/10 =5433      (2 digit)

Step 3:

reminder = 5433%10 = 3

digit =5433/10 =543           (3 digit)

Step 4:

reminder = 543%10 = 3

digit =543/10 =54          (4 digit)

Step 5:

reminder = 54%10 = 4

digit =54/10 =5         (5 digit)

Step 6:

reminder = 5%10 = 5

digit =5/10 =0           (6 digit)

now at last we get zero (0). it goes until we get quotient as zero. then count the number of steps, here are 6 steps so number of digits is here 6.

Program:

import java.util.*;
class Main
{
  int num;
  Scanner scan = new Scanner(System.in);
 
  public void length_sum_digits(){
     System.out.println("Please enter a number.");
     num = scan.nextInt();
     int sum = 0, count = 0;
 
     while(num > 0){
       sum += num%10;
       num = num/10;
       count++;
    }
 
    System.out.println("Number of digits:"+ count);
    System.out.println("Summation of digits of number is "+sum);
 }

 public static void main(String[] args) {
   Main obj = new Main();
   obj.length_sum_digits();
 }
}

Output: